Question

factorise (a+b+c)square -( a+b+c)square for cls 9 pls urgent​

Answer 1

Answer:

Step-by-step explanation:

(a+b+c)² - (a+b+c)²

a²+b²+c²+2ab+2bc+2ca - (a²+b²+c²+2ab+2bc+2ca)

a²+b²+c²+2ab+2bc+2ca - a²-b²-c²-2ab-2bc-2ca ( opening the brackets)

=0 ( as everything will be cancel)

Answer 2

${(a + b + c)}^{2} - {(a + b + c)}^{2} \\ = ({a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca) - ({a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca) \\ = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca - {a}^{2} - {b}^{2} - {c}^{2} - 2ab - 2bc - 2ca \\ = 0$