factorise..._
(a+b) ka whole qu. - (a-b) ka whole qu.
Answers
Answered by
6
(a + b)³ - (a - b)³
using (a + b)³ = a³ + b³ + 3ab(a+b)
and (a -b)² = a³ - b³ - 3ab(a - b)
=> [a³ + b³ +3ab(a + b)] - [a³ - b³ - 3ab(a - b)]
=> a³ + b³ + 3a²b + 3ab² - a³ + b³ + 3a²b - 3ab²
( since - is outside the bracket, we change the symbols inside)
=> 2b³ + 2(3a²b)
= 2b(b² + 3a²)
Hope it helps dear friend ☺️✌️✌️
using (a + b)³ = a³ + b³ + 3ab(a+b)
and (a -b)² = a³ - b³ - 3ab(a - b)
=> [a³ + b³ +3ab(a + b)] - [a³ - b³ - 3ab(a - b)]
=> a³ + b³ + 3a²b + 3ab² - a³ + b³ + 3a²b - 3ab²
( since - is outside the bracket, we change the symbols inside)
=> 2b³ + 2(3a²b)
= 2b(b² + 3a²)
Hope it helps dear friend ☺️✌️✌️
Anonymous:
Nice answer broda!
Nice
Thanks broda (to both)
read question again bro.
it is wrong
a+ b ka whole square - a-b ka whole square
sorry I thought it was square
now check it
Superb Bro !
Answered by
8
Hey..
Hope it will help u..
Hope it will help u..
Attachments:
nice answer !
thanks
Similar questions