Question

Factorise:
a cube + 0.008
1 - 27a cube ​

Answer 1

Step-by-step explanation:

Given expression is 1−27a3

We can write the above expression as:

=13−(3a)3

Using the formula, a3−b3=(a−b)(a2+ab+b2), we get:

⇒(1−3a)[12+1×3a+(3a)2]

∴ (1−3a)(1+3a+9a2)

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