Question

factorise a cube + 343 b cube

Answer 1

a^3 + 343 b^3

= (a)^3 + (7b)^3

= ( a + 7b ) ( a^2 + 49b^2 - 7ab )

Using identity,

[ x^3 + y^3 = (x+y) (x^2 + y^2 - xy)]

Answer 2

Heya ✋

Let see your answer !!!!

$a ^{3} + 343b ^{3} \\ = (a )^{3} + (7b) ^{3} \\ = > (a + 7b)((a) ^{2} - a \times 7b + \\ ( 7b)^{2}) \\ = > (a + 7b)(a ^{2} - 7ab + 49b ^{2})$





Thanks :)))