Question

factorise a cube + 8 b cube + 24 C cube minus 18ABC​

Answer 1

Answer:

Hope this helps you....

Step-by-step explanation:

a^3+8b^3+27c^3-18abc

(a) ^3+(2b)^3+(3c)^3-3(a)(2b)(3c)

=(a+2b+4c)[a^2+(2b)^2+(3c)^2-(a)(2b)-(2b)(3c)

- (3c)(a)]

=(a+2b+4c)[a^2+4b^2+9c^2-2ba-6bc-3ac]