factorise a cube minus b cube + 1 + 3 a b
Answers
Answered by
47
a³ - b³ + 1 +3ab
= a³ + ( - b )³ + 1³ - 3 × a × ( - b ) × 1
= [ a+(-b)+1 ][a²+(-b)²+1²-a(-b)-(-b)1-1×a]
= ( a - b + 1 ) ( a² + b² + 1 + ab + b - a )
I hope this helps you.
= a³ + ( - b )³ + 1³ - 3 × a × ( - b ) × 1
= [ a+(-b)+1 ][a²+(-b)²+1²-a(-b)-(-b)1-1×a]
= ( a - b + 1 ) ( a² + b² + 1 + ab + b - a )
I hope this helps you.
Similar questions