Question

factorise a )m square - 3 M - 70 b) 7psquare + 21 Q square c )a power 4 minus 2 a square B square + b power 4 d)y square minus 7 y plus 12 please answer me fast and I will mark as the brainliest answer explain me with steps please

Answer 1

Answer:

Step-by-step explanation:

1 ) m² - 3m - 70

⇒ m² - 10m + 7m - 70

⇒ m ( m - 10 ) + 7 ( m - 10 )

⇒ ( m + 7 ) ( m - 10 )

2 ) 7p² + 21q²

We know that, a² + b² = ( a + b )² - 2ab

⇒ 7p² + 21q² = ( √7p + √21q )² - 2 ( √7p ) ( √21q )

⇒ 7p² + 21q² = ( √7p + √21q )² - 2√147 pq

3 ) a⁴ - 2a²b² + b⁴

⇒ ( a² ) ² - 2 ( a² ) ( b² ) + ( b² ) ²

This is of the form, x² + 2xy + y² which is equal to ( x + y )²

Hence,  a⁴ - 2a²b² + b⁴ = ( a² ) ² - 2 ( a² ) ( b² ) + ( b² ) ² = ( a² + b² )²

4 ) y² - 7y + 12

⇒ y² - 4y - 3y + 12

⇒ y ( y - 4 ) -3 ( y - 4 )

⇒ ( y - 3 ) ( y - 4 )

These are the required answers.

Hope they helped !!

Thanks !!

Answer 2

a) m^2 - 3m - 70

m^2 + 7m -10 m -70

m( m+7) -10( m +7)

( m-10)(m+7)

b) 7 p^2 +21 Q^2

7 ( p^2 + 3 Q^2)



a^2 + b^2 = ( a+b)^2 - 2ab

7( (p +√3 Q)^2 - 2 √3 p Q)


c) a^4 - 2 a^2 b ^2 + b^4

( a^2 - b^2)^2

d) y^2 - 7 y + 12

y^2 - 4y - 3y +12

y( y-4) -3( y -4)

( y-3)( y-4)

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