Question

factorise. a raise to power 12 x raise to the power 12 - a to the power 4 x to the power 12​

Answer 1

hope dis will help u

Answer 2

$a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a+x)(a-x)$

Step-by-step explanation:

Given : Expression $a^{12}x^4-a^4x^{12}$.

To find : Factories the expression ?

Solution :

To factories the expression take the common term out.

Write the expression $a^{12}x^4-a^4x^{12}$ as,

$a^{12}x^4-a^4x^{12}=a^4x^4(a^8-x^8)$

$a^{12}x^4-a^4x^{12}=a^4x^4((a^4)^2-(x^4)^2)$

Using algebraic property, $a^2-b^2=(a+b)(a-b)$

$a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^4-x^4)$

$a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)((a^2)^2-(x^2)^2)$

$a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a^2-x^2)$

$a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a+x)(a-x)$

Therefore, the factories form is $a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a+x)(a-x)$

#Learn more

A^2-b^2-a-b factories​

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