Math, asked by arindam36, 1 year ago

factorise. a raise to power 12 x raise to the power 12 - a to the power 4 x to the power 12​

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Answers

Answered by sweety1387
10

hope dis will help u

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Answered by pinquancaro
3

a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a+x)(a-x)

Step-by-step explanation:

Given : Expression a^{12}x^4-a^4x^{12}.

To find : Factories the expression ?

Solution :

To factories the expression take the common term out.

Write the expression a^{12}x^4-a^4x^{12} as,

a^{12}x^4-a^4x^{12}=a^4x^4(a^8-x^8)

a^{12}x^4-a^4x^{12}=a^4x^4((a^4)^2-(x^4)^2)

Using algebraic property, a^2-b^2=(a+b)(a-b)

a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^4-x^4)

a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)((a^2)^2-(x^2)^2)

a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a^2-x^2)

a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a+x)(a-x)

Therefore, the factories form is a^{12}x^4-a^4x^{12}=a^4x^4(a^4+x^4)(a^2+x^2)(a+x)(a-x)

#Learn more

A^2-b^2-a-b factories​

https://brainly.in/question/11948766

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