Question

factorise a raise to the power 6 minus 512 b raised to power 6

Answer 1

HELLO DEAR,

 (a-b)•(a2+ab+b2) =
            a3+a2b+ab2-ba2-b2a-b3 =
            a3+(a2b-ba2)+(ab2-b2a)-b3 =
            a3+0+0+b3 =
            a3+b3

  512  is the cube of   8 
a6 is the cube of   a2

b6 is the cube of   b2

Factorization is :
             (a2 - 8b2)  •  (a4 + 8a2b2 + 64b4) 

I HOPE ITS HELP YOU DEAR,
THANKS