Math, asked by shubh5013, 11 months ago

factorise a square - 3A - 54​

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Answered by protestant
10
\underline\bold{\huge{SOLUTIONS\: :}}

a^{2} - 3a - 54

Find two factor such that their sum is

-3a and product is -54

We know that -9×6=-54 and their sum is

-9+6=-3

So -9 and 6 are the numbers.

a^{2} - 9a + 6a - 54

a(a - 9) + 6(a - 9)

(a - 9)(a + 6)

Now put

(a - 9) = 0

a = 9

Again put

(a + 6) = 0

a = - 6

But your answer is to find the factor

So it's factor are

(a+ 6) \: and \: (a - 9)

protestant: Hi your answer
Answered by Hemjass
4

Answer:

I hope this will help you ☺️☺️

Step-by-step explanation:

Answer:

a^2-3a-54

=a^2+6a-9a-54

=a(a+6)-9(a+6)

=(a-9)(a+6)

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