Question

factorise a square - 3A - 54​

Answer 1

$\underline\bold{\huge{SOLUTIONS\: :}}$

$a^{2} - 3a - 54$

Find two factor such that their sum is

-3a and product is -54

We know that -9×6=-54 and their sum is

-9+6=-3

So -9 and 6 are the numbers.

$a^{2} - 9a + 6a - 54$

$a(a - 9) + 6(a - 9)$

$(a - 9)(a + 6)$

Now put

$(a - 9) = 0$

$a = 9$

Again put

$(a + 6) = 0$

$a = - 6$

But your answer is to find the factor

So it's factor are

$(a+ 6) \: and \: (a - 9)$

Answer 2

Answer:

I hope this will help you ☺️☺️

Step-by-step explanation:

Answer:

a^2-3a-54

=a^2+6a-9a-54

=a(a+6)-9(a+6)

=(a-9)(a+6)