Question

factorise a square B square minus 6 A B C plus 9 c square​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Given,

to factorise a²b² - 6abc + 9c²

It is seen that the algebraic identity (a-b)² = a²- 2ab + b² will be used

Therefore,

$(ab)^{2}$-2(ab)(3c)+$(3c)^{2}$

=$(ab-3c)^{2}$

=(ab-3c)(ab-3c)

is the answer