Question

Factorise : a square minus 2ab plus b square minus c square

Answer 1

Given:-

$a^2-2ab+b^2-c^2$

$\implies a^2-ab-ab+b^2-c^2$

Take commons:-

$\implies a(a-b)-b(a-b)-c^2$

$\implies (a-b)(a-b)-c^2$

$\implies (a-b)^2-c^2$

We know: $a^2-b^2=(a+b)(a-b)$

$\implies (a-b-c)(a-b+c)$

Hope it helped you mate!

Answer 2

Answer:

(a-b-c) (a-b+c)

Step-by-step explanation:

Given:-

a^2-2ab+b^2-c^2a

2

−2ab+b

2

−c

2

\implies a^2-ab-ab+b^2-c^2⟹a

2

−ab−ab+b

2

−c

2

Take commons:-

\implies a(a-b)-b(a-b)-c^2⟹a(a−b)−b(a−b)−c

2

\implies (a-b)(a-b)-c^2⟹(a−b)(a−b)−c

2

\implies (a-b)^2-c^2⟹(a−b)

2

−c

2

We know: a^2-b^2=(a+b)(a-b)a

2

−b

2

=(a+b)(a−b)

\implies (a-b-c)(a-b+c)⟹(a−b−c)(a−b+c)