Question

Factorise
a) (x-2y) square + 7 (x - 2y) + 12
b) (3a - b) square - 4 (3a -b) + 4
c) (3x - 4y) square + 2 (3x - 4y ) - 35​

Answer 1

Answer:

a) (7x - 14y - 4)(x - 2y - 3)

Step-by-step explanation:

Given Equation is 7(x - 2y)² - 25(x - 2y) + 12

= 7(x - 2y)² - 21(x - 2y) - 4(x - 2y) + 12

= 7(x - 2y)[(x - 2y) - 3] - 4[(x - 2y) - 3]

= 7(x - 2y)[x - 2y - 3] - 4[x - 2y - 3]

= [7(x - 2y) - 4][x- 2y - 3]

= (7x - 14y - 4)(x - 2y - 3)

b)x^(3)-12x(x-4)-64

x^(3)-64-12x(x-4)

this is the form of (a-b)³ = a³-b³-3ab(a-b)

x³-4³-3(4)(x)(4-x)

∴ (x-4)³

c) (3x)²-2(3x*4y)+4y²+2(3x-4y)-35

(cancel + and - expressions)

{(3x)²-(4y)²}-35 [a²-b²=a+b*a-b]

→(3x+4y)(3x-4y)-35