Question

factorise a. x2 -8x +7​

Answer 1

We have,

$\quad \: {x}^{2} - 8x + 7 \\ \\ = {x}^{2} - (7 + 1)x + 7 \\ \\ = {x}^{2} - 7x - x + 7 \\ \\ = x(x - 7) - 1(x - 7) \\ \\ = (x - 7)(x - 1)$
Henceforth,
$\underline{ \boxed{ \quad \tt\red{ {x}^{2} - 8x + 7} \quad = \quad \tt\green{(x - 7)(x - 1)} \quad}}$

Answer 2

SolutioN:-

♀ x² - 8x + 7

=> x² - ( 7 + 1 )x + 7

=> x² - 7x - x + 7

=> x ( x - 1) - 7 ( x- 1)

=> (x - 1) ( x - 7)

Verification:

=> ( x -1)( x - 7)

=> x ( x - 7 ) -1(x - 7)

=> x² - 7x -x + 7

=> x² - 8x + 7

Hence, verified

So , factors are ( x -1 ) ( x- 7)

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How to factorise :-

• First split the middle term.
• Then take common
• And solve.