Question

factorise a²+1-(6/a²)
please give me the correct answer with steps please dont just answer for points​

Answer 1

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Given:

$a^2 + 1 - \frac{6}{a^2} = 0a2+1−a26=0$

To Find:

• Factories the given equation.

Solution:

   

$⇒     a^2 + 1 - \frac{6}{a^2} = 0a2+1−a26=0$

     

$⇒          \frac{a^4 + a^2 - 6 }{a^2} = 0a2a4+a2−6=0$

     

$⇒     a^4 + a^2 - 6 = 0a4+a2−6=0$

Rewriting the equation splitting the middle term using the two factors ,  -2  and  3

       ⇒    a^4 - 2a^2 + 3a^2 - 6 = 0a4−2a2+3a2−6=0

       ⇒   a^2 (a^2-2) + 3 (a^2 - 2) = 0a2(a2−2)+3(a2−2)=0

       ⇒   (a^2-2) (a^2 + 3) = 0(a2−2)(a2+3)=0

•       This is the desired factorization.