Question

factorise a2+1/a2+2-5a-5/a​

Answer 1

Answer:

(a+1/a){(a+1/a)-5}

Step-by-step explanation:

a2+1/a2+2-5a-5/a

=(a+1/a)^2-5(a+1/a)

=(a+1/a){(a+1/a)-5}

Answer 2

Step-by-step explanation:

$a^{2}+\frac{1}{a^{2}}+2-5a-\frac{5}{a}$

$= [(a)^{2}+(\frac{1}{a})^{2}+2×a×\frac{1}{a}]-5(a+\frac{1}{a})$

$= (a+\frac{1}{a})^{2}-5(a+\frac{1}{a})$

$= (a+\frac{1}{a}) (a+\frac{1}{a}-5)$