factorise a² + 1/a² - 5a + 2 - 5/a
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Answer:
a² + 1/a² - 5a + 2 - 5/a
= a²+1/a²-5a-5/a+2
= a²+1/a²-5(a+1/a)+2
= (a+1/a)²-2-5(a+1/a)+2
= (a+1/a)²-5(a+1/a)
= (a+1/a)[(a+1/a)-5]
= (a+1/a)(a+1/a-5)
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