Question

factorise: a2 - 10ab-75b2​

Answer 1

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "b2" was replaced by "b^2". 1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

((a2) - 10ab) - (23•3b2)

STEP

2

:

Trying to factor a multi variable polynomial

2.1 Factoring a2 - 10ab - 24b2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (a + 2b)•(a - 12b)

Answer 2

Answer:

Step-by-step explanation:

a²+10ab-75b²

First, factorize the '10ab' by dividing it into two numbers which when multiplied are 75 (because of our last term) and when subtracted (because of the sign before 75) are 10 (because of the term itself.)

So, such numbers are 15 and 5. [15*5=75, 15-5=10]

= a²+(15-5)ab-75b²

Now, multiply both the terms with ab.

= a²+15ab-5ab-75b²

Now, take the common terms by dividing the term into two. (a²+15ab and -5ab-75b²)

The common from a²+15ab is a so we take 'a' common and leave the rest in a bracket like this: a(a+15b). The common from -5ab-75b² is -5 so we take '-5' common and leave the rest in a bracket like : -5(a+15b).

= a(a+15b)-5b(a+15b)

As we ended up with two (a+15b)'s we combine them to one bracket and leave the rest in another bracket like:

= (a+15b) (a-5b)

Thus the correct answer to this is:

(a+15b) (a-5b)