Factorise a2-15a+36 in the form x2+bx+c
Answers
Answer:
Factoring a2-15a+36
The first term is, a2 its coefficient is 1 .
The middle term is, -15a its coefficient is -15 .
The last term, "the constant", is +36
Step-1 : Multiply the coefficient of the first term by the constant 1 • 36 = 36
Step-2 : Find two factors of 36 whose sum equals the coefficient of the middle term, which is -15 .
-36 + -1 = -37 -18 + -2 = -20 -12 + -3 = -15 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and -3
a2 - 12a - 3a - 36
Step-4 : Add up the first 2 terms, pulling out like factors :
a • (a-12)
Add up the last 2 terms, pulling out common factors :
3 • (a-12)
Step-5 : Add up the four terms of step 4 :
(a-3) • (a-12)
Which is the desired factorization
Final result :
(a - 3) • (a - 12)
Step-by-step explanation:
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