Math, asked by sujanju718, 1 year ago

Factorise: (a2 - 2a)^2 – 23(a^2 – 2a) +120​

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Answered by ayush1234567i9
4

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Answered by misscutie94
2

Answer:

Question :-

➠ (a² - 2a)² - 23(a² - 2a) + 120

Answer :-

➠ (a² - 2a)² - 23(a² - 2a) + 120

➻ (a² - 2a)² - 15(a² - 2a) - 8(a² - 2a) + 120

➻ (a² - 2a) (a² - 2a - 15) - 8(a² - 2a - 15)

➻ (a² - 2a - 15) (a² - 2a - 8)

➻ {a² - (5 - 3)a - 15} {a² - (4 - 2)a - 8}

➻ {a² - 5a + 3a - 15} {a² - 4a + 2a - 8}

➻ {a(a - 5) + 3(a - 5)} {a(a - 4) + 2(a - 4)}

➻ {(a - 5) (a + 3)} {(a - 4) (a + 2)}

➻ (a - 5) (a + 3) (a - 4) (a + 2)

∴ The value of (a² - 2a)² - 23(a² - 2a) + 120 is (a - 5) (a + 3) (a - 4) (a + 2)

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