factorise a²+2ab+b²-9c²
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Hii...
Here is ur answer :--
a^2+2ab+b^2-9c^2
= (a+b)^2 - 9c^2
So, we solve this by using identity a ^2 - b^2
( a+b+9c) [a+ b (-9c) ]
( a+b+9c) (a+b-9c)
Hope it helps!!
Here is ur answer :--
a^2+2ab+b^2-9c^2
= (a+b)^2 - 9c^2
So, we solve this by using identity a ^2 - b^2
( a+b+9c) [a+ b (-9c) ]
( a+b+9c) (a+b-9c)
Hope it helps!!
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