factorise (a2 -2ab+b2) -c2
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Solution:
(a²-2ab+b²) - c²
= (a-b)² - c²
/* x²-2xy+y² = (x-y)² */
= (a-b+c)(a-b-c)
/* x²-y² = (x+y)(x-y) */
Therefore,,
(a²-2ab+b²) - c² = (a-b+c)(a-b-c)
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