Question

factorise a² +86² +64 c3 – 24 abc​

Answer 1

Answer:

{(a+2b+4c)(a²+4 b²+16 c²-2 ab-8 bc-4 ca)

Step-by-step explanation:

a³+ 8 b³+64 c³- 24 a bc

using a³+b³ +c³-3 a bc =[ (a+b+c)(a²+ b² + c² -ab -bc - ca)]

identity

(a)³+(2 b)³+(4 c)³-3(a)(2 b)(4 c)

= [(a+2 b+4 c){a² +(2 b)²+(4c)²-a x 2b - 2b x 4c - 4c x a}]

= {(a+2b+4c)(a²+4 b²+16 c²-2 ab-8 bc-4 ca)