Factorise a²-(a - b + c)^2
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Answered by
2
Answer:
Answer:
a²-(b-c)² = (a+b-c)(a-b+c)
Explanation:
Factorising a²-(b-c)²
_______________________
we know the algebraic identity:
\boxed {x^{2}-y^{2}=(x+y)(x-y)}
x
2
−y
2
=(x+y)(x−y)
_______________________
= [a+(b-c)][a-(b-c)]
= (a+b-c)(a-b+c)
Therefore,
a²-(b-c)² = (a+b-c)(a-b+c)
••••
Answered by
0
Step-by-step explanation:
a²-(a-b+c)²
=a²-(a²+b²+c²-2ab-2bc+2ac)
=a²-a²-b²-c²+2ab+2bc-2ac
=a²-b²-c²+2ab+2bc-2ac
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