Question

factorise a2+ ab+ bc+ ac​

Answer 1

$\huge \bold \red{hello \: mate}$

a²+ab+bc+ac=0

Now, on rearranging the like terms,

a²+ab+ac+bc=0

Taking a and c as common,

=a(a+b)+c(a+b)=0

=(a+b)(a+c)=0

Answer: (a+b)(a+c)