Question

factorise a²-(b-c)²​

Answer 1

a²-(b-c)²

=[a-(b-c)]×[a+(b-c)] ......{by identity a²-b²=(a+b)(a-b)}

=(a-b+c)×(a+b-c)

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Answer 2

=(a-(b-c) x(a+(b-c) (b2(a+b)(a-b)

=(a-b+c)x(a+b-c)