factorise : a2 (b – c) + b (c – b) don't give me irrelevent answers
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Answered by
2
Step-by-step explanation:
a²(b-c)+b(c-b)=0
multiplying both sides by -1 we get
-1[a²(b-c)+b(c-b)]=0
a²(c-b)-b(c-b)=0
(a²-b)(c-b)=0
a²-b=0 , c-b=0
a=√b , c=b
Answered by
0
Answer:
a2(b-c) -b(b-c)
(b-c)(a2-b)
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