Question

factorise a² + b² + 2 (a b + BC + CA)​

Answer 1

Step-by-step explanation:

As we know, p^2 + q^2 + 2pq = (p + q)^2

We get,

= ( a+b)^2 + 2bc + 2ca

= ( a+b)^2 + 2c( b + a )

Or

( a+b)^2 + 2c( a + b )

Take ( a + b ) as common factor;

= ( a + b )( a + b + 2c )

Therefore,

a^2 + b^2 + 2ab + 2bc + 2ca = ( a + b )( a + b + 2c )