factorise a²+b²+2ab-81
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Answer:
by rearranging
a^2+2ab+ b^2- 81
( as per comparison between (a+b)^2 identity)
=( a+b) ^2- 81
= ( a+b) ^2 -(9) ^2
=(a+b+9) (a+b-9) ( using a^2-b^2 identity)
hope it will help you
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