factorise a²-b²+2bc-c²
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Answered by
2
Answer:
Given : a
2
−b
2
+2bc−c
2
We can write it as
a
2
−b
2
+2bc−c
2
=a
2
−(b
2
−2bc+c
2
)
We know that, (a−b)
2
=a
2
−2ab−b
2
a
2
−b
2
+2bc−c
2
=a
2
−(b−c)
2
Based on the equation a
2
−b
2
=(a+b)(a−b)
We get,
a
2
−b
2
+2bc−c
2
=[a+(b−c)[a−(b−c)]
a
2
−b
2
+2bc−c
2
=(a+b−c)(a−b+c)
By taking (2a+3b) as common
a 2 −b 2 +2bc−c 2
=(2a+3b)(2a−3b−1)
Step-by-step explanation:
I hope it's helpful to you ^_^
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Answered by
9
Answer:
Hello Avika how are you dear sista?
Good Afternoon
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