Question

factorise (a2-b2)3+(b2-c2)3+(c2-a2)3

Answer 1

Answer:

=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)

Step-by-step explanation:

(a2-b2)3+(b2-c2)3+(c2-a2)3

We find

a2-b2+b2-c2+c2-a2=0

so(a2-b2)3+(b2-c2)3+(b2-c2)3

=3(a2-b2)(b2-c2)(b2-c2)

=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)