Question

Factorise a2 - b2 - 4ac +4c2

Answer 1

Answer:

(a)2+(2c)2-2×a×2c-b2

(a-2c)2-b2

(a-2c+b) (a-2c-b)

Answer 2

Answer:

${a}^{2} - {b}^{2} - 4ac + 4c {}^{2} \\ = {a}^{2} - 4ac + 4 {c}^{2} - {b}^{2} \\ = {(a - 2c)}^{2} + (2c - b)(2c + b)$

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