Question

Factorise=[a²-b²-4ac+4c²] [5star+Bralliant answer].

Answer 1

$= a ^{2} + (2c)^{2} - 2(a)(2c) - b ^{2} \\ using \: identity \: (a - b) ^{2} = a^{2} + b ^{2} - 2ab \\ (a - 2c) ^{2} - b^{2} \\ using \: identity \: a ^{2} - b^{2} = (a + b)(a - b) \\ (a - 2c - b)(a - 2c + b)$

Answer 2

= a²+2(c)²-2(a)(2c) -b

using identity (a-b)² = a²+b²-2ab

(a-2c)² -b²

using identity:- a²-b² = (a+b)(a-b)

(a-2c-b) (a-2c+b)

I hope it's helpful for you......

mark as on brainlist answer......