Question

factorise :
(a2+b2-4c2)2-4a2b2​

Answer 1

Step  1  :

Equation at the end of step  1  :

 ((((a2)+(b2))-(4•(c2)))•2)-(22a2•b2)

Step  2  :

Equation at the end of step  2  :

 ((((a2)+(b2))-22c2)•2)-22a2b2

Step  3  :

Trying to factor a multi variable polynomial :

3.1    Factoring    a2 + b2 - 4c2  

Try to factor this multi-variable trinomial using trial and error  

Factorization fails

Equation at the end of step  3  :

 2 • (a2 + b2 - 4c2) -  22a2b2

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  -4a2b2 + 2a2 + 2b2 - 8c2  =  

 -2 • (2a2b2 - a2 - b2 + 4c2)  

Final result :

 -2 • (2a2b2 - a2 - b2 + 4c2)

Answer 2

Explanation in the above image....

a2-b2=(a+b) (a-b) using this identity we have to solve the problem...

if u like it mark it as brainliest answer...

Hope this helps u....