Math, asked by ivy3715, 10 days ago

Factorise:
(a²-b²)c+(b²-c²)a​

Answers

Answered by SwarajBose
1

Answer:

(a-c)(ac + b^{2} )

Step-by-step explanation:

(a^{2}  - b^{2} )c + (b^{2}  - c^{2} )a

= a^2c-b^2c + b^2a - c^2a

= a^2c - c^2a + b^2a - b^2c

= ac(a-c) + b^2(a-c)

= (a-c)(ac+b^2)

Answered by agarwalniha85
0

Answer:

Here is your answer

Step-by-step explanation:

(a

2

−b

2

)c + (b^{2} - c^{2} )a(b

2

−c

2

)a

= a^2c-b^2c + b^2a - c^2aa

2

c−b

2

c+b

2

a−c

2

a

= a^2c - c^2a + b^2a - b^2ca

2

c−c

2

a+b

2

a−b

2

c

= ac(a-c) + b^2(a-c)ac(a−c)+b

2

(a−c)

= (a-c)(ac+b^2)(a−c)(ac+b

2

)

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