factorise a2-b2-c2+d2-2(ad-bc)
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Solution:
a²-b²-c²+d²-2(ad-bc)
=a²-b²-c²+d²-2ad+2bc
=a²+d²-2ad-b²-c²+2bc
=(a²+d²-2ad)-(b²+c²-2bc)
=(a-d)²-(b+c)²
=[(a-d)+(b+c)][(a-d)-(b+c)]
=(a-d+b+c)(a-d-b-c)
Or
=(a+b+c-d)(a-b-c-d)
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