Question

Factorise:
a²+bc+ab+ac=?​

Answer 1

Given

Factorise:

a²+bc+ab+ac

Solution

➟ a² + bc + ab + ac

➟ a² + ac + ab + bc

➟ a(a + c) + b(a + c)

➟ (a + c)(a + b)

Some Identities

• (a + b)² = a² + b² + 2ab
• (a - b)² = a² + b² - 2ab
• a² - b² = (a + b)(a - b)
• (a + b)³ = a³ + b³ + 3ab(a + b)
• (a - b)³ = a³ - b³ - 3ab(a - b)
• a³ - b³ = (a - b)(a² + ab + b²)
• a³ + b³ = (a + b)(a² - ab + b²)

$\rule{200}3$

Answer 2

Answer:

The above answer is write but only last step i.e.answer is wrong

it's.. (a+b) (a+c)