factorise a2 + BC + AB + AC
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a² + bc + ab + ac
Rearranging the terms , we get
= a² + ab + ac + bc
= ( a×a + a×b )+( a×c+b×c )
Take a and c common in
first and second brackets
respectively, we get
= a( a + b ) + c( a + b )
Again take ( a + b )
common , we get
= ( a + b )( a + c )
••••
Step-by-step explanation:
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