Question

factorise:a²bc+ab²c+abc²+abc​

Answer 1

Answer:

abc(a+b+c)

Step-by-step explanation:

a^2bc+ab^2+abc^2

take abc as common,

=abc [a^2bc/abc+ab^2c/abc+abc^2/abc]

=abc{a+b+c}

hence,the factores form abc=abc(a+b+c)