Math, asked by ankurchongdar, 1 year ago

factorise a²bx+2a²cx-2aby-4acy+bz+2cz

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Answered by khushipatel2108
9

a²bx + 2a²cx - 2aby - 4acy + bz + 2cz

= a²x (b + 2c) - 2ay (b + 2c) + z (b + 2c)

= (b + 2c) (a²x - 2ay + z),

which is the required factorization.

Answered by SulagnaRoutray
9

Heya mate,

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Ur answer is in the attachment.

Hope it helps u dear friend......

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