Factorise a²x - 4 ax + 3 ax² please explain this equation
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Solution:-
a²x - 4ax + 3ax²
Taking Common
→ ax ( a - 4 + 3x)
→ ax ( 3x + a -4)
Therefore, the required answer is ax ( 3x +a -4)
Additional Information!!
Some More identities!!
• (a + b)² = a² + b² +2ab
• ( a - b )² = a² + b² -2ab
• ( a² - b² ) = ( a - b ) ( a + b )
• ( a +b +c)² = (a² + b² + c²) + 2(ab + bc +ca)
• (a + b)³ = a³ + b³ + 3ab(a+b)
• (a-b)³ = a³ - b³ -3ab(a-b)
• ( a³ + b³) = (a+b) (a²-ab +b²)
• (a³ - b³) = (a -b) (a² + ab + b²)
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