Question

factorise a3 - 2 root 2

Answer 1

$The \: \: answer \: \: is \: \: given \: \: below :\\ \\ Now, \\ \\ {a}^{3} - 2 \sqrt{2} \\ \\ = {a}^{3} - {( \sqrt{2}) }^{3} \\ \\ = (a - \sqrt{2} )( {a}^{2} + a \sqrt{2} + {( \sqrt{2} )}^{2} ) \\ \\ = (a - \sqrt{2} )( {a}^{2} + a \sqrt{2} + 2) \\ \\ We \: \: used \: \: the \: \: identity, \\ \\ {a}^{3} - {b}^{3} \\ \\ = (a - b)( {a}^{2} + ab + {b}^{2} ) \\ \\ Than k\: \: you \: \: for \: \: your \: \: question.$

Answer 2

Hey!

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Factorise :-

a³ - 2√2

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Solution :-

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Identity :-

a³ - b³ = (a - b) (a² + ab + b²)

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= a³ - (2√2)³

= (a - √2) (a² + a√2 + (√2)²

= (a - √2) (a² + a√2 + 2)

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Answer = (a - √2) (a² + a√2 + 2)


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Regards :)

Cybary

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