Question

factorise a³+27b³. pls help me​

Answer 1

Answer:

We know that

(a + b)³ = a³ + b³ + 3ab(a + b)

So,

a³ + b³ = (a + b)³ - 3ab(a + b)

This can be simplified to the expression below.

(a + b) (a²ab + b²)

Thus, we have,

a³ + b³ = (a + b)(a² - ab + b²)

Now, coming to your question,

a³ +27b³ can be simplified as below.

(a)³ + (3b)³

Because 3³ = 27.

Using the identity,

(a)³ + (3b)³ = (a + 3b) ((a²) — (a)(3b) + (36)²) -

= (a + 3b)(a² - 3ab +96²)

Hence, the answer to your question is as below:

(a + 3b) (a²-3ab + 9b²)

Answer 2

x

${8 \times {y)(}^{2} }^{2}$