Question

Factorise - a³ + 3a² + 3a + 9
Please give the correct answer ​

Answer 1

Answer:

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Answer 2

Answer:

${a}^{3} + ( {3}^{a2} + 3a) + 9 \\ ({a}^{3} + 9) + ( {3}^{a2} + {3}^{a} ) \\ in \: second \: group \: {3} ^{a} \: is \: common \: so \: atq \\ ( {a}^{3} + 9) + ( {3}^{a} ( {a} + 1)) \\ {3}^{a}( {a} + 1)( {a}^{3} + 9) \: \: \: \: is \: your \: answer$