Question

factorise a3 -3a2b +3ab2 +2b3

Answer 1

GIVEN :

Factorise the expression  $a^3 -3a^2b +3ab^2+2b^3$

TO FIND :

The factors of the given expression by using factorisation method.

SOLUTION :

Given expression is $a^3 -3a^2b +3ab^2+2b^3$

Now factorise the given expression  $a^3 -3a^2b +3ab^2+2b^3$

That is solving the expression $a^3 -3a^2b +3ab^2+2b^3$ as below:

$a^3 -3a^2b +3ab^2+2b^3$

Rewritting the above expression for our convenient to solve it we get,

$=a^3 -3a^2b +3ab^2+3b^3-b^3$

$=(a^3 -3a^2b +3ab^2-b^3)+3b^3$

By using the algebraic identity :

$(a-b)^3=a^3-3a^2b+3ab^2-b^3$

$=(a-b)^3+3b^3$

∴ $a^3 -3a^2b +3ab^2+2b^3=(a-b)^3+3b^3$

∴ the given expression $a^3 -3a^2b +3ab^2+2b^3$ is factorised into $(a-b)^3+3b^3$

Answer 2

Answer:

sorry bro

Step-by-step explanation: