Question

Factorise: a³+ 3a²b + 3ab² +b² - 8

Answer 1

We know that,

[a³+b³+3a²b+3ab²=(a+b)³]

So,

(a+b)³-(2)³

We know that,

[a³-b³=(a-b)(a²+ab+b²)]

So,

(a+b)³-(2)³=

[(a+b)-2][(a+b)²+(a+b)(2)+(2)²]=

(a+b-2)(a²+b²+2ab+2a+2b+4) ANSWER...

HOPE THIS HELPS YOU:-))