factorise
a³+3a²b+3ab²+b³-8
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a³+3a²b+3ab²+b³-8
= a³ + 3ab(a + b) + b³- (2)³
= (a - 2)³
= (a-2)(a-2)(a-2) Ans
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Answered by ➳ MrKrishhh~✨
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