Question

Factorise a3+3a2b+3ab2+b3-8

Answer 1

a^3 + 3a^b + 3ab^2 + b^3 - 8
= (a + b ) ^ 3 - (2)^3
=( a + b - 2 ) ( a^2 + b ^2 + 2ab +4 + 2a + 2b) ans.

Answer 2

(a3+3a2b+3ab2+b3)-2 power3

=(a+b)3-2power3

=(a+b-2)((a+b)2+(a+b)(2)+2power2

=(a+b-2)(a2+2ab+b2+2a+2b+4)