Question

Factorise

a³+3a²b+3ab²+b³-8​

Answer 1

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hello...!

a³+3a²b+3ab²+b³-8

using identity↪

» a³+3a²b+3ab²+b³=(a+b)³

» (a+b)³-8

» (a+b)³-(2)³

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Answer 2

$a \times a \times a + 3 \times a \times a \times b + 3 \times a \times b \times b + b \times b \times b - 8$
this is the answer I hope it will help you

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