Factorise: a³ - 3a²b + 3b² - 2b³
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Answer:
a3 - 3a2b - 2b3 + 3b2
Step-by-step explanation:
(a3)-(3•(a2)•b)+(3•(b2)-2b3
(a3)-(3•(a2)•b)+3b2)-2b3
(a3) - (3a2 • b) + 3b2) - 2b3
4.1 a3-3a2b-2b3+3b2 is not a perfect cube
a3 - 3a2b - 2b3 + 3b2
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a³–3a²b+3ab²–2b³
= a³ – 3a²b + 3ab² – b³ – b³
= (a–b)³ – b³
= (a–b–b) {(a–b)²+ (a–b)b + b²}
= (a–2b) (a²+b²–ab)
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